---
id: 65578fcf00322dbad5dee05b
title: Passo 38
challengeType: 20
dashedName: step-38
---

# --description--

Create an `if` statement to check if the distance of the neighbor node (the second item in the processed tuple) plus the distance of `current` is less than the currently known distance of the neighbor node (the first item in the processed tuple).

Use the `pass` keyword to temporarily fill the body of the `if`.

# --hints--

You should have an `if` statement to check if `distance + distances[current]` is less than `distances[node]`.

```js
({ test: () =>  {
    const shortest = __helpers.python.getDef(code, "shortest_path");
    const {function_body} = shortest;    
    assert(function_body.match(/^(\s*)for\s+\w+\s*,\s*\w+\s+in\s+graph\s*\[\s*current\s*\]\s*:\s*^\1(\s{4})if\s+distance\s*\+\s*distances\s*\[\s*current\s*\]\s*<\s*distances\s*\[\s*node\s*\]\s*:/ms));
  }
})
```

# --seed--

## --seed-contents--

```py
my_graph = {
    'A': [('B', 3), ('D', 1)],
    'B': [('A', 3), ('C', 4)],
    'C': [('B', 4), ('D', 7)],
    'D': [('A', 1), ('C', 7)]
}

def shortest_path(graph, start):
    unvisited = list(graph)
    distances = {node: 0 if node == start else float('inf') for node in graph}
    paths = {node: [] for node in graph}
    paths[start].append(start)

    while unvisited:
        current = min(unvisited, key=distances.get)
--fcc-editable-region--
        for node, distance in graph[current]:
            pass
--fcc-editable-region--    
    print(f'Unvisited: {unvisited}\nDistances: {distances}\nPaths: {paths}')

#shortest_path(my_graph, 'A')

```
